NettetExplanation: a and b are two integer variables. p stores address of a and q stores address of b. by performing p = q, p now stores the address of b Output int a = 7; int b = 17; int *c = &b; *c = 7; cout << a << " “ << b << endl; 7 17 17 7 7 7 17 17 Answer: 7 7 Explanation: c stores the address of variable b. Nettet18. sep. 2013 · int a = 2; int b = a++ + a++; //right to left value of first a++=2 and then a=3 so second a++=3 after that a=4 b=3+2; b=5; int a = 2; int b = a++;int c = a++;int d = b …
Output of C programs Set 52 - GeeksforGeeks
NettetIf your variables are the same type, you can define multiple variables in one declaration statement. For example: int age, reach; In this example, two variables called age and … Nettetint a, b, c; This declares three variables ( a, b and c ), all of them of type int, and has exactly the same meaning as: 1 2 3 int a; int b; int c; To see what variable … Provides information about the properties of arithmetic types (either integral or … This program prints on screen the final values of a and b (4 and 7, respectively). … gold bond maximum relief anti-itch cream 1 oz
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Nettet12. okt. 2024 · Let us understand the execution line by line. Initial values of a and b are 1. // Since a is 1, the expression --b // is not executed because // of the short-circuit … NettetUPU International Bureau Weltpoststrasse 4 . 3015 BERNE . SWITZERLAND designated operators. T +41 31 350 31 11 . F +41 31 350 31 10 . www.upu.int . Contact: Mr Javier … Nettet9. mar. 2024 · 4 Answers Sorted by: 7 The line int a, b = 0; is equivalent to int a; int b = 0; So, relative to int a = 0; int b = 0; the difference is that a is not initialized. In your specific code, since you have things like while (p < n-1) { the execution is not determinable - p has not had an initial value set. Share Improve this answer Follow gold bond maximum relief anti-itch cream